you will be given a line "packaged" according to a certain rule: & nbsp;
note that the lines can be invested in each other. For example, & nbsp; One line without gaps containing the lowercase letters of the Latin alphabet, the numbers and square brackets & nbsp; One line & mdash; The result of complete unpacking. 3 [a] 2 [bc] aaabcbc accaccaccacccaccccccaccccccccccacccccccccccaccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc Kid
Input format
Output format
Example
Input
Output
Hint
There will be no clue here, decide for yourself!
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RU
def unpack_string(s: str) -> str:
"""
Распаковывает строку вида k[substring], включая вложенные структуры.
"""
stack = []
current_num = 0
current_string = ''
for char in s:
if char.isdigit():
# Собираем число, если оно многозначное (например, 10, 12)
current_num = current_num * 10 + int(char)
elif char == '[':
# Начало новой подстроки. Сохраняем текущее состояние в стек.
# Сохраняем текущую строку и число-повторитель для нее.
stack.append(current_string)
stack.append(current_num)
# Сбрасываем переменные для нового уровня вложенности.
current_string = ''
current_num = 0
elif char == ']':
# Конец подстроки. Достаем из стека предыдущее состояние.
num = stack.pop()
prev_string = stack.pop()
# Формируем новую текущую строку, повторяя распакованный фрагмент
# и добавляя его к строке предыдущего уровня.
current_string = prev_string + current_string * num
else:
# Просто добавляем букву к текущей строке.
current_string += char
return current_string
input_string = input()
result = unpack_string(input_string)
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Running your code...