THEORY AND PRACTICE

Input and Output Data

Tasks

Conditions

Tasks

For Loop

Tasks

Strings

Tasks

While Loop

Tasks

Lists

Tasks

Two-Dimensional Arrays

Tasks

Dictionaries

Tasks

Sets

Tasks

Functions and Recursion

Tasks

Занятие 9. Sets

Difficulty level:

Task«Participants and their interests»

Imagine that you are the organizer of the interests at school. You have a list of students attending various circles (drawing, music, chess, programming, etc.). Your task & ndash; Make a list of all students who are engaged in at least one of the circles. In other words, you need to find the association of all lists of students attending every circle.

Input format

first the number & nbsp; n & nbsp; & ndash; The number of circles. Further, in & nbsp; n & nbsp; lines are entered information about each circle. In each line, the number & nbsp; k & ndash; The number of students in the circle, and then through the gap, the names of the students visiting this circle are listed. The names of students & ndash; These are lines that do not contain gaps

Output format

Draw a list of all students who attend at least one circle in alphabetical order, sharing the names of students with spaces

Example

Input

3
2 Alice Bob
3 Charlie David Alice
1 Eve

Output

Hint

Comparing sets

Subset

A set A is a subset of set B if all elements of set A, without exception, are also contained in set B. The issubset() method is used to check this condition. and the operator .

A useful tip: The <= operator checks for a "non-strict" subset. This means that any set is a subset of itself (set1<= set1 returns True). If you need to check that the set A is a subset of B, but it is not equal to it, use the strict inequality operator .

set1 = {1, 2}
set2 = {1, 2, 3}
set3 = {1, 2}

# Checking for a subset
print(set1.issubset(set2))  # Output: True
print(set1 <= set2) # Output: True

# Checking for a strict subset
print(set1 < set2) # Output: True
print(set3< set1) # Output: False, since the sets are equal

Superset

A set A is a superset of set B if it contains all the elements that are in set B. The issuperset() method is used for verification. and the operator =.

A useful tip: Similarly to subsets, the = operator checks for a "non-strict" superset. To check for a strict superset (A contains all the elements of B and at least one additional one), use the operator.

set1 = {1, 2, 3}
set2 = {1, 2}

# Checking for a superset
print(set1.issuperset(set2))  # Output: True
print(set1 >= set2) # Output: True

# Checking for a strict superset
print(set1 > set2) # Output: True
print(set1 > {1, 2, 3}) # Conclusion: False, since the sets are equal

Equality of sets

Sets are considered equal if they contain exactly the same set of elements. The order of the elements does not matter at all. The == operator is used for verification.

set1 = {1, 2, 3}
set2 = {3, 2, 1}
set3 = {1, 2, 3, 3} # The duplicate will be ignored when creating a set.

print(set1 == set2) # Output: True
print(set1 == set3) # Output: True

Other set methods

Copying a set

The copy() method returns a surface copy of the set.

Important advice: Do not confuse copying with assignment. If you write set2 = set1, then set2 will not be a new set, but only another reference to set1. Changing set2 will change set1. Use copy() to create an independent array.

set1 = {1, 2, 3}

# Correct copying
set2 = set1.copy()
set2.add(4)
print(f"Original set1: {set1}")  # Output: Original set1: {1, 2, 3}
print(f"Copy of set2: {set2}")    # Output: A copy of set2: {1, 2, 3, 4}

# Incorrect copying (link assignment)
set3 = set1
set3.add(5)
print(f"Original set1 after changing set3: {set1}") # Output: Original set1 after changing set3: {1, 2, 3, 5}
print(f"Reference set3: {set3}")                       # Output: set3 link: {1, 2, 3, 5}

Updating the set

The update() method adds to the current set all the elements from another set or any other iterable object (for example, a list or a tuple). The method modifies the original set and returns nothing (None).

set1 = {1, 2, 3}
set2 = {3, 4, 5}
list1 = [5, 6, 7]

set1.update(set2) # Duplicate {3} will be ignored
print(set1) # Output: {1, 2, 3, 4, 5}

set1.update(list1) # You can update it from the list
print(set1) # Output: {1, 2, 3, 4, 5, 6, 7}

Sets and their applications

Arrays are extremely useful in various tasks due to their speed and unique properties. They are ideal for removing duplicates, quickly checking for an element, and performing mathematical operations (union, intersection, difference).

Removing duplicates from the list

This is one of the most common uses of arrays. Converting a list to a set automatically removes all duplicates. Then, if necessary, the set can be converted back to a list.

It is important to remember: With this transformation, the original order of the list items is not preserved.

numbers = [1, 2, 2, 3, 4, 4, 5, 1]
unique_numbers = list(set(numbers))
print(unique_numbers) # The output can be [1, 2, 3, 4, 5] ( the order is not guaranteed)

Search for common items in two lists

To find the elements that are present in both collections, you can transform them into sets and use the intersection operator &.

list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]
common_elements = list(set(list1) & set(list2))
print(common_elements)  # Output: [3, 4] (order is not guaranteed)

Search for unique elements (symmetric difference)

To find the elements that are in one of the lists, but not both at once, use the symmetric difference operator ^.

list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]
unique_to_each_list = list(set(list1) ^ set(list2))
print(unique_to_each_list) # Output: [1, 2, 5, 6] ( the order is not guaranteed)

main.py

Test 1

Test 2

Test 3

Test 4

Test 5

Test 6

Test 7

Test 8

Test 9

Test 10

Developer’s solution

🎉 Congratulations! 🎉

You did an excellent job with the task! It was a challenging problem, but you found the correct solution. You are one step closer to mastering programming! Keep up the good work, because every stage you pass makes you even stronger.