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Занятие 5. While cycle

Difficulty level:

Task«Summer of numbers with a pass»

your school accounting collects donations for the repair of the gym. To simplify accounting, it was decided not to take into account small and some specific amounts. The chief accountant decided that during the final calculation, you need to ignore all the amounts of donations that are divided by 3 or 5. All other amounts must be folded.

rn

You need to write a program that will ask the user as a summ donations one after another. The user introduces integers. The input process ends when the user introduces the word & nbsp; After that, the program should display the total amount of donations that were taken into account according to the rules of accounting.

Input format

The user enters the data line. Each line contains either a whole number (type & nbsp; number , which is read as & nbsp; line ), or The word & nbsp; stop & nbsp; (Type & nbsp; line ), which is a signal for completing the input.

Output format

The program displays a single number (type & nbsp; number ) & mdash; The total amount of donations that satisfy the condition.

Example

Input

100
50
27
11
7
Stop

Output

18

Hint

While in python

In the Python programming language, the while loop construction can have an optional else block. This block is executed only when the loop completes in its natural way, that is, when its condition becomes false, and not as a result of a forced interruption using the break operator.

Syntax:

while condition:
    # the body of the loop
    # ...the code that runs on each iteration...
else:
    # else block
    # ...the code that is executed if the loop ended without a break...

You can think of the else block as a "plan B": it is triggered if the main goal within the loop (which is usually completed through a break) has not been achieved.

Usage example: Searching for an element

Consider a classic problem where we search for a number in a list. If a number is found, we immediately break the loop using break. If we have checked all the elements and still haven't found what we are looking for, the else block is executed.

numbers = [1, 2, 3, 4, 5]
target = 8 # Let's try to find a number that is not in the list.

index = 0
while index < len(numbers):
    if numbers[index] == target:
        print(f"Success! {target} found at {index}.")
break # Goal reached, exit the loop
    index += 1
else:
    # This block will be executed because break was not called
    print(f"The search is completed. {target} not found in the list.")

How it works:

  1. The whileloop is executed as long as the index < len(numbers) condition is true.
  2. Inside the loop, we check whether the current element is equal to the desired one (target).
  3. If we find a value, a success message is displayed and the loop is immediately interrupted by the break statement. The else block is ignored in this case.
  4. If the loop reaches the end (checked all the elements), it means that break has never worked. The index < len(numbers) condition becomes false, and then the else block is executed, reporting a failed search.

A useful tip: Using while...else helps to avoid "flagged" variables. Without this block, the code would look like this:

# Alternative version with "flag"
numbers = [1, 2, 3, 4, 5]
target = 8
found = False # Flag variable

index = 0
while index < len(numbers):
    if numbers[index] == target:
        found = True
        break
    index += 1

if found:
    print(f"Success! {target} found.")
else:
print(f"Search completed. {target} not found in the list.")

As you can see, the while...else construction makes the code cleaner, more concise, and more "Pythonic", eliminating the need to manually control the flag.

If break is missing

If there is no break operator in the body of the while loop, then the else block will always be executed after the loop ends.

count = 0
while count < 3:
print(f"Iteration number {count}")
count += 1
else:
print("The loop ended naturally, so the else block is executed.")

Here, the while loop runs until count is less than 3. As soon as count becomes 3, the loop condition becomes false, and control is transferred to the else block.

Important nuances

  • What about continue? The continue operator does not interrupt the loop, but only ends the current iteration ahead of schedule. It does not affect the execution of the else block in any way.
  • If the loop was never executed? If the while condition is initially false, the loop body will not be executed even once. However, the else block will still run, since the loop ended "normally" (it was not interrupted via break).
value = 10
while value < 5: # The condition is immediately false
    print("This text will never be printed")
else:
print("The cycle didn't even start, but it ended normally, so else worked.")
  • This also works for for loops! The same logic applies to for...else loops. The else block after for is executed if the cycle has passed through all the elements and has not been interrupted using break.

Output

The while...else construction is a powerful and elegant Python tool. It is ideal for situations where you need to perform an action only if the loop has completed its work completely without being interrupted. This is especially useful in search algorithms, condition checking, or when working with data streams, where break signals a special event, and else indicates a regular termination without any.

main.py
Test 1
Test 2
Test 3
Test 4
Test 5
Test 6
Test 7
Test 8
Test 9
Test 10
Developer’s solution
# Инициализируем переменную для хранения общей суммы пожертвований.
# Начинаем с нуля, так как еще ничего не посчитано.
total_sum = 0

# Создаем бесконечный цикл для непрерывного ввода данных.
# Цикл прервется только специальной командой.
while True:
    # Запрашиваем у пользователя ввод (это может быть число или слово "стоп").
    # Введенные данные всегда считываются как строка.
    donation_input = input()

    # Проверяем, ввел ли пользователь слово "стоп" для завершения работы.
    # Это наше условие выхода из цикла while.
    if donation_input == 'стоп':
        # Если пользователь ввел "стоп", выходим из бесконечного цикла.
        break

    # Если введено не "стоп", то это должна быть сумма.
    # Преобразуем введенную строку в целое число для математических операций.
    donation = int(donation_input)

    # Это главное условие задачи. Проверяем, что сумма не делится на 3 И не делится на 5.
    # Оператор % (остаток от деления) помогает это выяснить.
    # Если остаток от деления на 3 не равен 0 И остаток от деления на 5 не равен 0, то...
    if donation % 3 != 0 and donation % 5 != 0:
        # ...добавляем эту сумму к нашей общей сумме.
        total_sum = total_sum + donation

# После завершения цикла (когда было введено "стоп") выводим итоговую посчитанную сумму.
print(total_sum)

🎉 Congratulations! 🎉

You did an excellent job with the task! It was a challenging problem, but you found the correct solution. You are one step closer to mastering programming! Keep up the good work, because every stage you pass makes you even stronger.

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Помощник ИИ

Привет! Я твой помощник по программированию. Задавай любые вопросы по Python, я могу рассказать о функциях, методах, обьяснить то, что тебе не понятно, а так же о текущей задаче!