Get a key

"

something like this:

  d = {  1 :  ', , .  '2' :  2 ,   3 :  '' 3 ', }   def   get_key  ( d, value ):   for  k, v  in  d.items ():   if  v == value:   retu  k  print  (d,  '' 1 ') ))   print  (get_key (d,  2 ))   print  (get_key (d,  42 ))     
 console: 
  
   1    2    none      
 in general, when I need to get the key and key key, I conquer two dictionaries. 
  
 
 
                                    

obtaining a symbol by its number from Unicode:

   & gt; & gt; & gt;   chr  ( 65 )   'a' a '   chr  ( 122 )   'z'    & gt; & gt; & gt;   print  ( 128522 )) ?    
 is better instead of instead  chr  use  unichr 
  
 receipt of the number from the unicode by the symbol: 
  
   & gt; & gt; & gt;   Ord  ( 'a' )   65    Ord  ( 'z' )   122    & gt; & gt; & gt;   Ord  ( '?' )   128522      
 in pre -prepared Latin (and not only) symbols in the symbols. The  string : 
  
   & gt; & gt; & gt;   Import  string  & gt; & gt; & gt;  string.ascii_uppercase  '"abcDephhijklmnopqrsstuvwxyz'    & gt; & gt; & gt;  string.ascii_lowercase  '"abcodefghijklmnopqrsstuvwxyz'    & gt; & gt; & gt;  string.Askii_letters  '"abcDefhijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz'    
  
 It is a cycle: 
  
   for  c  in  string.ascii_letters:   print  (c)     
 in all generator expressions and conditions, of course, too: 
  
  & gt; & gt; & gt;   Import  string  & gt; & gt; & gt;  s =  '' foo, take the barotsudbazinlatinskoye '   & gt; & gt; & gt;  s2 =  ''  .join (c  in  s  if  in  in  string.ascii_letters)   & gt; & gt; & gt;   print  (s2) foobarbaz