A way out of several cycles

   for  item  in  items:   if> some_condition:   break      
 in order to get out of several cycles according to the condition that is executed in the inteal cycle, the output flag is used, which initially matters  false , and if necessary, exit the cycle prematurely accepts the value  True : 
  
  Flag =  false    for  than  in  out_list:   for  inner  in  inner_list:   if  some_condition:  flag =  true    break    if  flag:   Break      
 Thus, you can get out of any number of embedded cycles, you just need to add a check to the output flag. 
  
  The second, beautiful  
  
 you should change the structure of your code a little. To begin with, make checks on the entry of words from the  blacklist  and  Whitelist  in a separate function: 
  
   def   containes_words  ( text, words_list ):   for  word  in  buts_list:   if  text.find (word)! = - 1 :   retu   true    retu   false      
 now check for the entry of words from  Whitelist  Blacklist  will look like this: 
  
   for  text  in  in  some_text:   if  containe (text, Whitelist)  and   not  containe (text, BlackList):   print  ()   else :   print  ( "" Not Found "" )   
  
 expressions  not contacts_words (Text, Blacklist) , since, whatever it is, the meaning of the expression  containe (Text, Whitelist) and NOT) and NOT Contains_Words (Text_blacklist)  will always be  false 
.