Why do you need Lambda functions?

They cannot be 100% , that is, it is impossible to write a program without workings, without lambda -function - it is possible, but it is shorter and more convenient with them. For example, you need to print a dictionary in decreasing order of each value:

  Bigrams = {: [ 10 ,  11 ,  12 ], : [ 5 , - 5 ,  8 ], : [ 105 ,  1 ,  0 ],  : [ 6 ,  6 ], " "EF" ": [ 15 ,  20 ,  15 ], : [ 22 ,  11 ,  32 ],  : [ 20 ,  20 ,  20 ]} sorter =  sorted  (bigrams, key =  lambda  key:  sum  (bigrams [key]), reverse =  true )   for  key  in  sorter:   print  (key, bigrams [key])     
 otherwise you need to write a function: 
  
   from  functools  import  partial  def   sort_func  ( key,  dict  ):   retu   sum  ( dict  [key]) bigrams = {: [ 10 ,  11 ,  12 ], : [ 5 , - 5 ,  8 ],  "" cd "" : [ 105 ,  1 ,  0 ],   "de" ": [ 6 ,  6 ], : [ 15 ,  20 ,  15 ], : [ 22 ,  11 ,  32 ],   "gh" ": [ 20 ,  20 ,  20 ]} partial_Sort = PARTIAL (SORT_FUNC,  dict  = Bigrams) sorter =  sorted  (bigrams.keys (), key = partial_sort, reverse =  true )   for  key  in  sorter:   print  (key, bigrams [key])     
 the result is the same, but not with the lambda, not You need to look for the eyes of  sort_FUNC  - it is immediately clear how exactly the collection is sorted. The standard library is full of functions that take other functions:  map ,  reduce ,  filter ,  sorted ,  a man ,  all  
  
 you can write a closure: 
  
   DeF   access  ( x ):   retu   lambda  y: x + yead_to_ten = Addition ( 10 )   print  (add_to_ten ( 8 ))   print  (ad_to_ten ( 6 ))     
 in theory, the Lambda function is absolutely the same as ordinary functions, but without a name: 
  
 Class = "" Data-Highlighted = "">  def   funch  ( x ):  func =  lambda  x: x +  1    retu   100    import  DIS  print  (Dis.dis (FUNC))     
 shows that a new function is really created, without fraud.